Light extinction due to DOCLight extinction due to DOChttps://oss.deltares.nl/c/message_boards/find_thread?p_l_id=183924&threadId=4199282024-03-28T19:16:47Z2024-03-28T19:16:47ZRE: Light extinction due to DOCMichelle Jeukenhttps://oss.deltares.nl/c/message_boards/find_message?p_l_id=183924&messageId=4206352014-05-02T11:59:46Z2014-05-02T09:32:08ZHi Ingrid,<br /><br />I see no reason why it should be an hidden option, so I changed some flags. This version of the proc_def should make it available in the PLCT. You can replace it in your Delft3D installation, usually somewhere in c:\Program Files (x86)\Deltares\Delft3D 4.01.00\win32\waq\bin\.<br /><br /><br />greetings,<br />Michel<br /><br />P.S.: Another work around (in case you need an other hidden parameter or output) would be to add the parameter to the sub-file, see an example below. This way you can still use the delwaq GUI. However, you can't load the substance file into the PLCT, so if you update your model with the PLCT, you need to add your manual changes to the sub-file again.<br /><br />parameter 'RcMrtEColi'<br /> description 'first-order mortality rate EColi'<br /> unit '(1/d)'<br /> value 0.8000E+00<br />end-parameterMichelle Jeuken2014-05-02T09:32:08ZLight extinction due to DOCIngrid Holzwarthhttps://oss.deltares.nl/c/message_boards/find_message?p_l_id=183924&messageId=4199272014-04-30T12:40:49Z2014-04-30T12:40:49ZDear Delwaq-Forum,<br /><br />I use the DYNAMO-module to simulate algae growth and activate the radiation-limitation function. Therefore, the total extinction coefficient has to be calculated.<br /><br />If I use th GUI, I can choose different specific attenution coefficients which are multiplied by the concentration of the specific substance (e.g. Diatoms or POC1) to result in a contribution to the total extinction coefficient. <br />However, I don't find a possibilty to choose a specific coefficient for DOC and my results for ExtVlODS (which should contain the partial attenuation due to DOC) contain only zeros. <br />Do I have to activate this part separately from the other partial attenuations?<br /><br />Best regards,<br />IngridIngrid Holzwarth2014-04-30T12:40:49Z